I can't seem to get this right.

Move all terms containing xx to the left side of the inequality.

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Since xx contains the variable to solve for, move it to the left side of the inequality by subtracting xx from both sides.

2x−5−x>−22⁢x-5-⁢x>-2

Subtract xx from 2x2⁢x to get xx.

x−5>−2x-5>-2

Move all terms not containing xx to the right side of the inequality.

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Since −5-5 does not contain the variable to solve for, move it to the right side of the inequality by adding 55 to both sides.

x>5−2x>5-2

Subtract 22 from 55 to get 33.

x>3

First get everything one side

 

x^2-2x-5=0

x^2-2x = 5         Take 1/2 of the 'x' coefficient and square it and add it to both sides

x^2 - 2x +1 = 5 + 1

(x-1)^2 = 6

x-1 = +-sqrt 6

x= 1 + sqrt 6     and  1- sqrt 6