+3454 I'm thinking you mean
log3(2x−1)=2
To do this, we need to rewirte this is exponential form!
What log3(2x−1)=2 is saying, is that 32=2x−1
Now that we have it like this its pretty easy to solve.
3^2 = 2x-1
9 = 2x-1
10=2x
x=5
Here's a website explaining why you can change the log into exponets like i did. I thought they explained it well. http://www.mathsisfun.com/algebra/exponents-logarithms.html
+3454 I'm thinking you mean
log3(2x−1)=2
To do this, we need to rewirte this is exponential form!
What log3(2x−1)=2 is saying, is that 32=2x−1
Now that we have it like this its pretty easy to solve.
3^2 = 2x-1
9 = 2x-1
10=2x
x=5
Here's a website explaining why you can change the log into exponets like i did. I thought they explained it well. http://www.mathsisfun.com/algebra/exponents-logarithms.html
