how would you sketch a line whose equation is y=4/3x+1 using the gradient intercept method
I'm thinking this is the same as the 'slope intercept' method...here is what I would do;
When the line crosses the 'y' axis 'x' is equal to zero....so to find this 'y' value set 'x' to zero:
y= 4/3 (0) + 1 == 1 so one point to plot is x,y = 0,1
Similar thing for the 'x' axis where 'y' will equal ZERO
0= 4/3 x + 1 = x= -3/4 so the next point to plot is x,y = -3/4 , 0
now draw a line through these points and there ya have it!