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The period PP (in seconds) of a pendulum is given by the function P=2π√ L/32, where L is the pendulum length (in feet). What is the length of a pendulum with a period of 0.75 second? Round your answer to the nearest hundredth of a foot.

 Mar 23, 2020
 #1
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P =  2pi√(L/32)

 

0.75  = 2pi √ (L/32)       divide both sides  by  2pi

 

0.75  /  (2 pi )   = √[ (L /32)      square both sides

 

[ 0.75 / (2pi) ]^2 =  L/32    multiply both sides by 32

 

32 * [ 0.75 / (2pi) ] ^2  = L  ≈ .46  ft

 

 

cool cool cool

 Mar 23, 2020

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