The period PP (in seconds) of a pendulum is given by the function P=2π√ L/32, where L is the pendulum length (in feet). What is the length of a pendulum with a period of 0.75 second? Round your answer to the nearest hundredth of a foot.
P = 2pi√(L/32)
0.75 = 2pi √ (L/32) divide both sides by 2pi
0.75 / (2 pi ) = √[ (L /32) square both sides
[ 0.75 / (2pi) ]^2 = L/32 multiply both sides by 32
32 * [ 0.75 / (2pi) ] ^2 = L ≈ .46 ft
