We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive pseudonymised information about your use of our website.
Please click on "Accept cookies" if you agree to the setting of cookies. Cookies that do not require consent remain unaffected by this, see
cookie policy and privacy policy.
DECLINE COOKIES

http://web2.0calc.com/questions/1-nbsp-suppose-we-have-a-bag-with-8-slips-of-paper-in-it-six-of-these-have-a-1-on-them-and-the-other-two-have-a-3-on-them-what-is-the-ex

Guest Apr 19, 2015

#1**+5 **

The expected value is the average. So if we have 6 slips of paper with 1 and 2 slips with 3, to get the average we add up all the numbers and divide by the total number of slips, which would give us:

average = (1 + 1 + 1 + 1 + 1 + 1 + 3 + 3)/8 = 12/8 = 3/2

But notice that there are 6 lots of 1 and 2 lots of 3, so we could write this as (6*1 + 2*3)/8

The 6 and the 2 are known as "weights".

Notice also that the total number of slips is the same as the sum of the "weights": 6 + 2 = 8.

Whenever you have grouped data (that is, a number of slips with the same value) it tends to be easier to calculate the average by multiplying the "weight" by the number in each group, adding up the results of all the "weights"*numbers and then dividing the whole lot by the sum of all the weights.

Does this make it any clearer?

Alan Apr 19, 2015