If t(x) = 3-g(x) and g(x) = √x, then what is t(g(16))?
Let's find g(16) .
g(x) = √x
Plug in 16 for x .
g(16) = √16
g(16) = 4
Now let's find t(4) .
t(x) = 3 - g(x)
Plug in 4 for x .
t(4) = 3 - g(4)
And g(4) = √4 = 2 so we can substitute 2 in for g(4)
t(4) = 3 - 2
t(4) = 1
So.....
t( g(16) ) = t( 4 ) = 1