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GetThere Airlines currently charges  200 dollars per ticket and sells 40,000 tickets a week. For every  10 dollars they increase the ticket price, they sell  800 fewer tickets a week. How many dollars should they charge to maximize their total revenue?

 Jan 29, 2021
edited by Mapear  Jan 29, 2021
 #1
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Ans: ticket price should be= $ 350

soln:

current revenue=$ 200*40,000=$ 8,000,000

now, let they suppose  increase the price by=$ 10*x, x is a natural number

no ticket loss per week will be= 800*x

now, revenue =f(revenue)=(200+10*x)*(40,000-800*x)= -8,000*x2+240,000*x+8,000,000

for maximum or minimum--differentiating f(revenue)=0

=>-16000*x+240,000 = 0

=>x=15

by double differentiating f(revenue) we get <0

=>at x=15 it will be maximum value.

Ans:ticket should be= $200 + $ 10*15 =$ 350.

 

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 Jan 29, 2021
 #2
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Christ! Anyone that can decipher your bullshit infused slop could more easily figure out how to solve the problem without it.

 

Here’s CPhill’s solution: https://web2.0calc.com/questions/please-help-me-thank-you_5

 

 

GA

GingerAle  Jan 29, 2021

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