Six students measure the acceleration (in meters per second per second) of an object in free fall. The measured values are: 10.56, 9.52, 9.73, 9.80, 9.78, 10.91.
The students want to state that the absolute deviation of each measured value x from the mean is at most d.
Find the value of d
+33653 First find the mean: mean = (10.56 + 9.52 + 9.73 + 9.80 + 9.78 + 10.91)/6 → 10.05
Now find the absolute value of the deviations of each value from the mean:
|10.56 - 10.05| = 0.51
|9.52 - 10.05| = 0.53
|9.73 - 10.05| = 0.32
|9.80 - 10.05| = 0.25
|9.78 - 10.05| = 0.27
|10.91 - 10.05| = 0.86
The maximum absolute deviation is 0.86, so d = 0.86
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