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The edge of a cube is increased by 20%. What is the percentage increase in its surface area?

 Jan 13, 2020
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The suface area   = 6s^2    where s is the side of the cube

 

So....now with the increase....the side  = 1.2s

 

So

 

The new surface area  =     6  [ (1.2)s ] ^2  =   8.64s^2

 

So....the percentage increase  =

 

[  8.64 - 6  ] / 6   x   100%   =   0.44 x 100%  =   44% 

 

 

cool cool cool

 Jan 13, 2020

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