web2.0calc
 
+0  
 

I dont really know how to do this

0
35
4
avatar

hi! So let me give you the question then my thoughts

question- Points T and U lie on a circle centered at O, and point P is outside the circle such that \(\overline{PT}\) and  \(\overline{PU}\) are tangent to the circle. If \(\angle TPO=26^\circ\), then what is the measure of minor arc TU, in degrees?

 

My thoughts- I was thinking about creating right triangles using the tangents to create right triangles so I can use the degrees. I dont know if my thoughts were correct... I still want to know how other people might go about this question

Thanks in advance

~Wolf 

 Jun 21, 2020

4+0 Answers

 #1
avatar
0

Arc TU = 4*26 = 104 degrees.

 Jun 21, 2020
 #2
avatar
0

hmm I dont really see your logic behind that answer

~ Wolf

Guest Jun 21, 2020
 #3
avatar+132 
+2

I myself posted this question as well. Later I figured out that it was 128 degrees. If you have any questions, I think that Geno's answer really helped.

 

https://web2.0calc.com/questions/lines-tangent-to-a-circle-please-explain

 Jun 21, 2020
 #4
avatar
0

wow! thank you!

~Wolf

Guest Jun 21, 2020

10 Online Users

Top Users

avatar+111394 CPhill moderator
avatar+109731 Melody moderator
avatar+30335 Alan moderator
avatar+25255 heureka
avatar+24570 ElectricPavlov
avatar+21566 geno3141
avatar+12269 Omi67 moderator
avatar+11886 rosala
avatar+9666 asinus moderator
avatar+8964 hectictar
avatar+8258 MaxWong

Sticky Topics