I dont understand how to solve this, A satelite is 720 kilometers above Earth, which has a radius of 6360 Kilos. The reigon of earth that is visible from the sattelite is between the tangent lines BA and BC. What s BA?
I think I have the idea, FM......
We have two congruent right triangles.....where BA is the leg of one [ and BC is the corresponding congruent leg of the other right triangle ]
The distance from the center of the Earth to the satellite is the hypotenuse of both triangles =
[ 6360 + 720] km = 7080 km
And the radius of the Earth - 6360 km - forms the other congruent leg of both right triangles....
So...BA is the remaining unknown leg of one of the right triangles
BA = √ [ 7080^2 - 6360^2 ] = about 3110.76 km [ this also = BC ]