Like the title states, I figured out how to prove ABCD is a rectangle, I just don't know how to find the area
Find the distance from B to C = sqrt [ (47 - 16)^2 + (34 - 16)^2 ] = (1)
Then....find the distance from A to B = sqrt [ (16 - 8)^2 + ( 34 - 20)^2 ] = (2)
Take the product of BC * AB = (1) * (2) = the area
Let me know if you get stuck ......
Thanks! I managed to get 592.5, but I'm not sure if it's correct...
After redoing it, I got 576.38...
sqrt [ (47 - 16)^2 + (34 - 16)^2 ] = sqrt [ 31^2 + 18^2] = sqrt [ 1285 ]
sqrt [ (16 - 8)^2 + (34 - 20)^2 ] = sqrt [ 8^2 + 14^2] = sqrt [ 260]
sqrt [ 1285 ] * sqrt [ 260] =
sqrt [ 1285 * 260] =
sqrt [ 334100] ≈ 578.01 units^2
Thank you :)