PQ is parallel to AC.....any segment drawn parallel to a base will create similar triangles
And triangle BPQ is similar to triangle BAC....so....we have the following relationship
BP /PQ = (BP + AP) / AC
2.2 / 2.6 = (2.2 + AP) / 5.6 cross-multiply
5.6 * 2.2 = 2.6 ( 2.2 + AP) simplify
12.32 = 5.72 + 2.6 AP
(12.32 - 5.72) / 2.6 = AP = 33/13 m ≈ 2.538 m