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I had my math finals today, and one question was that i had to use the Law of cosines i think its called, It was a triangle. AC=650m and BC=700 and grade C=121,1degrees. How long was ab?

 Apr 27, 2015

Best Answer 

 #1
avatar+23254 
+5

Law of Cosines:  c²  =  a² + b² -2abcos(C)

For this problem:  c = AB     a  =  BC = 700     b = AC = 650

--->                  c²  =  700² + 650² - 2(700)(650)cos(121.1°)

--->                  c²  =  1382545

--->                    c  =  1176.  

 Apr 27, 2015
 #1
avatar+23254 
+5
Best Answer

Law of Cosines:  c²  =  a² + b² -2abcos(C)

For this problem:  c = AB     a  =  BC = 700     b = AC = 650

--->                  c²  =  700² + 650² - 2(700)(650)cos(121.1°)

--->                  c²  =  1382545

--->                    c  =  1176.  

geno3141 Apr 27, 2015

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