I have a question about sigma notation. Here was what I was working on and its solution.
How did they come up with k/k+3 as a general term? Also the question was asking for the upper and lower limit summation. How did they come to 4 and 10 as the answer?
With each of these terms the denominator is 3 more than the numerator.
You could choose any letter (pronumeral) but they have chose the letter k to be a numerator.
If the numerator is k then the denominator would be k+3
So one way to describe each of these terms is $$\frac{k}{k+3}$$ so this can be used as the general term.
Now the first term is $${\frac{{\mathtt{4}}}{{\mathtt{7}}}}$$ so for the first term k=4
The second term is $${\frac{{\mathtt{5}}}{{\mathtt{8}}}}$$ so for the first term k=5
etc
The last term is $${\frac{{\mathtt{10}}}{{\mathtt{13}}}}$$ so for the first term k=10
so it is the sum of all those terms from k=4 to k=10
$$\sum\limits_{\;k=4}^{10}}\;\frac{k}{k+3}$$
Do you understand any better?
This could have been expressed in many ways
For instance
$$\\\sum\limits_{\;k=7}^{13}}\;\frac{k-3}{k}\\\\\\
\sum\limits_{\;a=7}^{13}}\;\frac{a-3}{a}\\\\\\
\sum\limits_{\;g=1}^{7}}\;\frac{g+3}{g+6}\\\\\\$$
these all describe exactly the same sum
With each of these terms the denominator is 3 more than the numerator.
You could choose any letter (pronumeral) but they have chose the letter k to be a numerator.
If the numerator is k then the denominator would be k+3
So one way to describe each of these terms is $$\frac{k}{k+3}$$ so this can be used as the general term.
Now the first term is $${\frac{{\mathtt{4}}}{{\mathtt{7}}}}$$ so for the first term k=4
The second term is $${\frac{{\mathtt{5}}}{{\mathtt{8}}}}$$ so for the first term k=5
etc
The last term is $${\frac{{\mathtt{10}}}{{\mathtt{13}}}}$$ so for the first term k=10
so it is the sum of all those terms from k=4 to k=10
$$\sum\limits_{\;k=4}^{10}}\;\frac{k}{k+3}$$
Do you understand any better?
This could have been expressed in many ways
For instance
$$\\\sum\limits_{\;k=7}^{13}}\;\frac{k-3}{k}\\\\\\
\sum\limits_{\;a=7}^{13}}\;\frac{a-3}{a}\\\\\\
\sum\limits_{\;g=1}^{7}}\;\frac{g+3}{g+6}\\\\\\$$
these all describe exactly the same sum