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I have a question about sigma notation. Here was what I was working on and its solution. 

How did they come up with k/k+3 as a general term? Also the question was asking for the upper and lower limit summation. How did they come to 4 and 10 as the answer? 

 Nov 15, 2014

Best Answer 

 #1
avatar+118723 
+5

With each of these terms the denominator is 3 more than the numerator.

You could choose any letter (pronumeral) but they have chose the letter k to be a numerator.

If the numerator is k then the denominator would be k+3

So one way to describe each of these terms is     $$\frac{k}{k+3}$$    so this can be used as the general term.

 

Now the first term is    $${\frac{{\mathtt{4}}}{{\mathtt{7}}}}$$      so for the first term k=4

The second term is      $${\frac{{\mathtt{5}}}{{\mathtt{8}}}}$$       so for the first term k=5

etc

The last  term is         $${\frac{{\mathtt{10}}}{{\mathtt{13}}}}$$       so for the first term k=10

 

so it is the sum of all those terms from k=4 to k=10

 

$$\sum\limits_{\;k=4}^{10}}\;\frac{k}{k+3}$$

 

Do you understand any better?

 

This could have been expressed in many ways

For instance

$$\\\sum\limits_{\;k=7}^{13}}\;\frac{k-3}{k}\\\\\\
\sum\limits_{\;a=7}^{13}}\;\frac{a-3}{a}\\\\\\
\sum\limits_{\;g=1}^{7}}\;\frac{g+3}{g+6}\\\\\\$$

 

these all describe exactly the same sum    

 Nov 16, 2014
 #1
avatar+118723 
+5
Best Answer

With each of these terms the denominator is 3 more than the numerator.

You could choose any letter (pronumeral) but they have chose the letter k to be a numerator.

If the numerator is k then the denominator would be k+3

So one way to describe each of these terms is     $$\frac{k}{k+3}$$    so this can be used as the general term.

 

Now the first term is    $${\frac{{\mathtt{4}}}{{\mathtt{7}}}}$$      so for the first term k=4

The second term is      $${\frac{{\mathtt{5}}}{{\mathtt{8}}}}$$       so for the first term k=5

etc

The last  term is         $${\frac{{\mathtt{10}}}{{\mathtt{13}}}}$$       so for the first term k=10

 

so it is the sum of all those terms from k=4 to k=10

 

$$\sum\limits_{\;k=4}^{10}}\;\frac{k}{k+3}$$

 

Do you understand any better?

 

This could have been expressed in many ways

For instance

$$\\\sum\limits_{\;k=7}^{13}}\;\frac{k-3}{k}\\\\\\
\sum\limits_{\;a=7}^{13}}\;\frac{a-3}{a}\\\\\\
\sum\limits_{\;g=1}^{7}}\;\frac{g+3}{g+6}\\\\\\$$

 

these all describe exactly the same sum    

Melody Nov 16, 2014

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