+0  
 
0
993
3
avatar+24 

I have an unlimited supply of standard 6-sided dice. What's the fewest number of dice that I have to simultaneously roll to be at least 90% likely to roll at least one 6?

 

I am aware that this is a repost, but could someone please provide an alternate solution?

 Aug 5, 2016
 #1
avatar
0

You have to roll at least 13 dice to get 90%+ probability of getting at least 1 six. In fact, the exact probability for 13 dice is: 11,839,990,891/(6^13) =90.65%(assuming fair 6-sided dice).

 Aug 5, 2016
 #2
avatar+24 
0

Yeah, but thats like just trial and error. You can't just say 13 because 13.

Username1233qw4  Aug 6, 2016
 #3
avatar+1349 
+2

Alan answers and explains the details of the solution to this exact question here.

 

http://web2.0calc.com/questions/please-explain-thoroughly-so-i-could-understand-the-procedures#r1

 Aug 6, 2016

27 Online Users

avatar
avatar
avatar
avatar