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I have an unlimited supply of standard 6-sided dice. What's the fewest number of dice that I have to simultaneously roll to be at least 90% likely to roll at least one 6?

I am aware that this is a repost, but could someone please provide an alternate solution?

Username1233qw4 Aug 5, 2016

#1**0 **

You have to roll at least 13 dice to get 90%+ probability of getting at least 1 six. In fact, the exact probability for 13 dice is: 11,839,990,891/(6^13) =90.65%(assuming fair 6-sided dice).

Guest Aug 5, 2016

#2**0 **

Yeah, but thats like just trial and error. You can't just say 13 because 13.

Username1233qw4
Aug 6, 2016

#3**+2 **

Alan answers and explains the details of the solution to this **exact **question here.

http://web2.0calc.com/questions/please-explain-thoroughly-so-i-could-understand-the-procedures#r1

GingerAle Aug 6, 2016