+24 I have an unlimited supply of standard 6-sided dice. What's the fewest number of dice that I have to simultaneously roll to be at least 90% likely to roll at least one 6?
I am aware that this is a repost, but could someone please provide an alternate solution?
You have to roll at least 13 dice to get 90%+ probability of getting at least 1 six. In fact, the exact probability for 13 dice is: 11,839,990,891/(6^13) =90.65%(assuming fair 6-sided dice).
+24 Yeah, but thats like just trial and error. You can't just say 13 because 13.
+2511 Alan answers and explains the details of the solution to this exact question here.
http://web2.0calc.com/questions/please-explain-thoroughly-so-i-could-understand-the-procedures#r1
