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Given the system of linear equations. {y=-4x-3 {x=y+3

 Feb 17, 2015

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 #1
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{y=-4x-3 {x=y+3  

Using the second equation   we have explicitly that x = y + 3....so....let's just substitute that into the first equation...so we have

y = -4(y + 3) - 3     simplify

y = -4y -12 - 3

y = - 4y -15       add 4y to both sides

5y = -15       divide both sides by 5

y = -3

And....since x =y + 3...then x must equal -3 + 3 = 0

So our solution is ( 0, -3)

 

 Feb 17, 2015
 #1
avatar+130514 
+5
Best Answer

{y=-4x-3 {x=y+3  

Using the second equation   we have explicitly that x = y + 3....so....let's just substitute that into the first equation...so we have

y = -4(y + 3) - 3     simplify

y = -4y -12 - 3

y = - 4y -15       add 4y to both sides

5y = -15       divide both sides by 5

y = -3

And....since x =y + 3...then x must equal -3 + 3 = 0

So our solution is ( 0, -3)

 

CPhill Feb 17, 2015

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