If k^n=nk^n-1 is true. Then can 2 = 1? As 2 = 2^1 = 1*2^0 = 1 * 1 = 1?
Your first statement is false. \(k^n \ne nk^{n-1}\)
I am not sure what contradiction you are trying to prove or disprove, but \(2^1 \neq 1 * 2^0\)
kn = nkn–1 is not true.
kn = kkn–1 is true.
.
+189 
