Points T and U are on circle K such that K is 2 units from TU. If TU = 14, what is the radius of the circle?
I don't know if this is exactly right, but I think the radius is 6.
Assuming K is the center.....if we bisect TU at M we get that TM = UM = 7
And KMU = KMT are congruent right triangles....so ...looking at one of these
KT = the radius and hypotenuse
KM is a leg = 2
TM is another leg = 7
The radius = sqrt ( 2^2 + 7^2) = sqrt ( 4 + 49) = sqrt (53)