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Simplify each equation.

-2u3y    25x3

-------- - --------

15xz5  14u2y2

Please show work and tell me how to do it, I am very confused and want to get better at these.

Please hurry me test is tomorrow

Mar 2, 2020
edited by Guest  Mar 2, 2020
edited by Guest  Mar 2, 2020

#1
+1

-2u3y              25x3

-------     -     ---------      =

15xz5          14u2y2

To subtract fractions, you need a common denominator; in this case, the common denominator is found by multiplying both denominators together:

Denominator of each fraction =  15xz5 · 14u2y2  =  210xz5u2y2

So, both the numerator and denominator of the first fraction must be multiplied by 14u2y2

Numerator of the first fraction =  -2u3y · 14u2y2  =   -28u5y3

And, both the numerator and denominator of the second fraction must be multiplied by 15xz5

Numerator of the second fraction  =  25x3 · 15xz5  =  375x4z5

The problem is now:     [ -28u5y3 / 210xz5u2y2  ]  -  [ 375x4z5 / 210xz5u2y2  ]

Combining the two numerators:  -28u5y3 - 375x4z5  over the common denominator:  210xz5u2y2  gives you your answer"

=     ( -28u5y3 - 375x4z5 ) / 210xz5u2y2

Mar 2, 2020

#1
+1

-2u3y              25x3

-------     -     ---------      =

15xz5          14u2y2

To subtract fractions, you need a common denominator; in this case, the common denominator is found by multiplying both denominators together:

Denominator of each fraction =  15xz5 · 14u2y2  =  210xz5u2y2

So, both the numerator and denominator of the first fraction must be multiplied by 14u2y2

Numerator of the first fraction =  -2u3y · 14u2y2  =   -28u5y3

And, both the numerator and denominator of the second fraction must be multiplied by 15xz5

Numerator of the second fraction  =  25x3 · 15xz5  =  375x4z5

The problem is now:     [ -28u5y3 / 210xz5u2y2  ]  -  [ 375x4z5 / 210xz5u2y2  ]

Combining the two numerators:  -28u5y3 - 375x4z5  over the common denominator:  210xz5u2y2  gives you your answer"

=     ( -28u5y3 - 375x4z5 ) / 210xz5u2y2

geno3141 Mar 2, 2020