+0  
 
-1
54
9
avatar+486 

An equation is shown below:

4(2x - 5) + 15 = 11

Write the steps you will use to solve the equation and explain each step.

 Feb 23, 2019
edited by HiylinLink  Feb 23, 2019
 #1
avatar+17253 
+3

You have posted a lot of very similar questions....you SHOULD be understanding how to get the answer......YOU try it and see what you get,,,,then, if you need more help , re-post on this thread.....   OK?   You CAN do it!  Try it.....cheeky

   After distributive property.....collect 'like' terms...... then.....

 Feb 23, 2019
edited by ElectricPavlov  Feb 23, 2019
 #2
avatar+486 
-3

I know I'm pretty sorry to for bugging evry one with these I so badly want to master these it's just each questions reveals a  new forum of a problem that the lesson didnent really depth into but I will try my self at it and I'll just post it here.

 Feb 23, 2019
 #3
avatar+267 
+2

4(2x -5) + 15 =11

Subtract 15 on both sides

4(2x- 5) =  - 4

Divide 4 on both sides

2x - 5 = -1

Add 5 on both sides

2x = 4

Divide both sides by 2 

X = 2

 

Hope this helps ;P

 Feb 23, 2019
 #4
avatar+486 
-1

I enede up getting 3.875 as the x but I'm not sure if this is right becasue when I check the soloution I ened up with 26 

 

What I did was apply the distrubitive property normally  

 

then added twenty to eleven divided it by 8 so I beilieve when it comes around here I hit my problem I don't think I'm doing something rght after the disributive properety?

 Feb 23, 2019
 #5
avatar
+1

4(2x-5) + 15 = 11

8x - 20 + 15 = 11

8x - 5 = 11

8x = 11 + 5

8x = 16

x = 16/8

x = 2

 

Doubke checking my work:

4(4-5) + 15  = 11

4(-1) + 15 = 11

-4 + 15 = 11

11 = 11

 

Therefore, x = 2.

 Feb 23, 2019
 #6
avatar+486 
-1

I guess my question is how did the -20 become a five?

HiylinLink  Feb 23, 2019
 #7
avatar+486 
-1

Or are you saying you added 15 to the -20 then did the rest?

 Feb 23, 2019
 #8
avatar+267 
+4

Yes he added 15 to -20 to get -5. There are different ways to do this problems the Guests way or my way or another way.

EmeraldWonder  Feb 23, 2019
 #9
avatar+486 
0

I would like to thaank all who helped me here the help is very much appriciated thanks so much : )

 Feb 23, 2019

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