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These 3 problems I'm having trouble with... can someone please help me

 

 May 5, 2020
 #1
avatar+8 
+1

1. When we multiply exponents we add the powers. So if we have one negative number we can do -1. -1+1 will equal 0 so the numbers can be -1 and 0.

2. For this one, we are dividing, or subtracting the powers. If we make the power of the quotient negative, the other has to be higher than three. Thus we could do the first blank to be four. 3-4=-1 so the second would be -1.

3. If the base of the product is ten and one factor is two, the other factor must be 5. When we multiple 2^-3 and 5^-3 we get 10^-6

 

Let me know if you need additional help!

 May 5, 2020
 #3
avatar+1502 
+2

The numbers for 1) can't be -1 and 0, since it would be 2^(-1) = 2^0. You mean 1 right?

hugomimihu  May 5, 2020
 #4
avatar+8 
0

Yes sorry that is what I meant

Sd99Sd99  May 5, 2020
 #5
avatar+1502 
+2

There should be a button next to "Flag" and "reply", which says "edit". You should edit your work to prevent further confusion.

hugomimihu  May 5, 2020
 #2
avatar+1502 
+2

anything to the 0th power is 1.

 

So 2^x * 2^y = 1.

 

RIght?

 

so if you have a number with a neg. exponent, it's basically the reciprocal of that.

 

Well, a number and it's reciprocal multiplied equals one. 

 

Just stick to 2^-1 * 2^1 = 2^0. We have (-1, 1)

 

 

Well, we know about reciprocals, so 2^3/ 2^(-3) = 8/ ( 1/8). That's 8^8 = 64. 64 = 2^6. We have -3 and 6.

 

 

so 1/8 times x^-3 = 10^y.

 

Huh.

 

Well then y must also be negative.

 

so, if 10^-3, it's 1/1000, so 1/8 * 1/125 = 1/1000.

 

Funny. 1/125 = 5^-3.

 

If you don't understand anything feel free to ask.

 May 5, 2020

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