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The equation 3/4(x) +1 =3/4(x) -7 is unsolvable and comes out as 1=-7, right?

 Dec 2, 2016

Best Answer 

 #1
avatar+53 
+5

Yes, that is right. 

 

\(\frac{3}{4} (x)+1=\frac{3}{4}(x)-7 \)

\(\frac{3x}{4}+1=\frac{3x}{4}-7\)

\((\frac{3x}{4}-\frac{3x}{4})+1=(\frac{3x}{4}-\frac{3x}{4})-7\)

\(1=-7\)

 Dec 2, 2016
 #1
avatar+53 
+5
Best Answer

Yes, that is right. 

 

\(\frac{3}{4} (x)+1=\frac{3}{4}(x)-7 \)

\(\frac{3x}{4}+1=\frac{3x}{4}-7\)

\((\frac{3x}{4}-\frac{3x}{4})+1=(\frac{3x}{4}-\frac{3x}{4})-7\)

\(1=-7\)

ItzCubez Dec 2, 2016
 #2
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0

Well, it's not unsolveable, the solution is just no solution. 

 Dec 2, 2016
 #3
avatar+53 
+5

That is a very good point. The equation is not "unsolvable" (I just did it) but there is \(\boxed{\text{No Solution}}\)

 Dec 2, 2016
 #4
avatar+165 
0

I came here excited to find a unsolvable equation, but noooOOOOOooo, it's just a no solution equation. :(

 Dec 2, 2016

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