The equation 3/4(x) +1 =3/4(x) -7 is unsolvable and comes out as 1=-7, right?
Yes, that is right.
\(\frac{3}{4} (x)+1=\frac{3}{4}(x)-7 \)
\(\frac{3x}{4}+1=\frac{3x}{4}-7\)
\((\frac{3x}{4}-\frac{3x}{4})+1=(\frac{3x}{4}-\frac{3x}{4})-7\)
\(1=-7\)
That is a very good point. The equation is not "unsolvable" (I just did it) but there is \(\boxed{\text{No Solution}}\)
I came here excited to find a unsolvable equation, but noooOOOOOooo, it's just a no solution equation. :(