I keep on getting 3.2s but i don't think thats correct
When solving this problem, take down to be negative and right to be positive. A ball is thrown horizontally from the top of a building 51.2 m high. The ball strikes the ground at a point 111 m from the base of the building. The acceleration of gravity is 9.8 m/s 2 . Find the time the ball is in motion. Answer in units of s.
The ball will hit the ground in t seconds
-51.2 = yo + vo t - 1/2 a t^2
-51.2 = 0 + 0 - 1/2 (9.8) t^2
t = 3.232 seconds