Write 4/27*[2^(3+m/3) + 2^(m/3)]^3 as a power of 2.
Please show all work used :0
Thank you!
Guest
0 mins ago
2^(3+m/3) = 2^3 * 2^m/3
so
4/27 ( 2^m/3 ( 2*3 +1) )^3 =
4/27 2^(m/3 *3)(9)^3
4/27 * 2^m 9^3
4/27 * 2^m (3^2)^3
4/3^3 * 2^m * (3^3)^2
4 * 2^m * 3^3
2^2 * 2^m * 27
2^(2+m) * 27
Guest
0 mins ago
2^(3+m/3) = 2^3 * 2^m/3
so
4/27 ( 2^m/3 ( 2*3 +1) )^3 =
4/27 2^(m/3 *3)(9)^3
4/27 * 2^m 9^3
4/27 * 2^m (3^2)^3
4/3^3 * 2^m * (3^3)^2
4 * 2^m * 3^3
2^2 * 2^m * 27
2^(2+m) * 27