Hint. :)
2x^2y=-x^2y+3x^2y
and
-6x^2y=-1x^2y-5x^2y
(x^4 - 2x^2y - 3y^2) / (x^2 - 6x^2y + 5y^2) =
[(x^2 - 3y) (x^2 + y)] / [(x^2 - 5y) (x^2 - y) ] .....this is as much as we can do......no factors "cancel"
