I NEED AN ANSWER TODAY PLS
An isosceles triangle and a rhombus have the same measure unity.
Rhombus: D=8 d=6 s=5
Isosceles triangle: s=x S=x+1
Find the value of x so the perimeter of the rhombus equals the double of the triangle's.
+129850 The perimeter of the rhombus is 4*5 = 20 units
I'm assuming that the x in the triangle refers to the measure of one of the equal sides
So the perimeter of the triangle = x + x + x + 1 = 3x + 1
And we have this:
20 = 2[ 3x + 1] divide both sides by 2
10 = 3x + 1 subtract 1 from both sides
9 = 3x divide by 3 on both sides
3 = x
Proof :
20 = 2[3*3 + 1]
20 = 2[10]
20 = 20
