For question 1, the answer needed is the coordinate of F' and question 2, the coordinate of L'.
The answers I got from working the problems out were (20/3, 28/3) and (-3, 1/2) respectively but upon graphing these answers, I don't feel like it's right.
For both questions, the center of the figure is (4, -2).
For question 1, I need to give the leftmost point and question two the bottom most point. I got the answers (9/4, -3) and (7/4, -2) respectively.
Could someone verify these answers for me? Thank you in advance!
(1) E = (0,0) F(1,5) G(7,2) center of dilation = (5,2) scale factor = 2
Dilation rule is
Reverse the signs on the coordinates of the center = ( -5 , -2)
The "new " coordinates are ( x - 5, y - 2)
Apply the scale factor = (2x - 10, 2y - 4)
Add back the center coordinates = ( 5, 2)
[ (2x - 10 + 5). ( 2y - 4 + 2) ] =
( 2x - 5 , 2y - 2)
E' = [ (2(0) - 5, 2(0)-2) ] = (-5, -2 )
F' = [ ( 2(1) - 5 , 2(5) -2) ] = ( -3, 8)
G' = [ 2(7) - 5, 2(2) - 2 ] = ( 9, 2)
See here :
2. Similar to 1
Reverse the coordinates of the center = (3,-3)
The "new" coordinates = [(x + 3 , (y - 3) ]
Apply the scale factor = ( (1/3)x + 1, (1/3)y - 1)
Add back the coordinates of the center
[ (1/3)x + 1 - 3 , (1/3)y - 1 +3 ] =
[ x/3 - 2 , y/3 - 2 ] =dilation rule
You should be able to finish this one by applying the dilation rule to L,M,N,P
Also....find the coordinates of the parallelogram at the bottom and use the same proceedure to find the dilation rule for the first one
For the second one....just apply the scale factor to the computed points you got in 1