Set it up as:
$${\frac{\left({\mathtt{2}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,\small\textbf+\,}}{\mathtt{1}}\right)}{\left({\mathtt{3}}{\mathtt{\,-\,}}{\mathtt{2}}\right)}} = -{\mathtt{7}}$$
First, simplify the denominator to get 1. Since any number over 1 is the same number, you get the answer
$${\mathtt{2}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,\small\textbf+\,}}{\mathtt{1}} = -{\mathtt{7}}$$
Subtract 1 from both sides to get
$${\mathtt{2}}{\mathtt{\,\times\,}}{\mathtt{x}} = -{\mathtt{7}}$$
Then, just divide both sides by 2 and you're done!
$${\mathtt{x}} = -{\mathtt{3.5}}$$
Hope this helped!
:D
Thanks for answering CreeperCosmo but I do believe you have made a small mistake.
Since you are a member you can edit your answer and fix it.
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This question could also be interpreted differently. It could be;
$$2x+\frac{1}{3}-2=-7\\
\mbox{ or}\\
\frac{2x+1}{3}-2=-7\\$$
Maybe the asker could tell us which was required.
The motto is - Always use brackets, even when using words!