A helicopter flying 1,600 feet above the ground spots an airplane flying above. If the horizontal distance between the helicopter and airplane is 3,055 feet and the angle of elevation is 71°, find the airplane’s altitude.

Guest May 3, 2018

#1**+1 **

Let the height of the plane above the helicopter be "h"

We have a right triangle where the side opposite the 71 degree angle = h and the side adjacent to this angle = 3055

So we can use the tangent here

tan (71) = h / 3055 multiply both sides by 3055

3055 * tan (71) = h ≈ 8872.4 ft

So.......the total altitude of the plane is

1600 + 8872.4 =

10472. 4 ft

CPhill
May 3, 2018