Find the limit of each using algebraic techniques.
1.
2.
1) should be obvious
2)
\(\dfrac{4-\sqrt{18-x}}{x-2} =\\ \dfrac{4-\sqrt{18-x}}{x-2} \dfrac{4+\sqrt{18-x}}{4+\sqrt{18-x}}= \\ \dfrac{16-(18-x)}{(x-2)(4+\sqrt{18-x})} =\\ \dfrac{1}{4+\sqrt{18-x}}\)
now plug x=2 in