+0

# I need help finding the limits

0
110
1

Find the limit of each using algebraic techniques.

1.

2.

Apr 17, 2019

#1
+5770
+2

1) should be obvious

2)

$$\dfrac{4-\sqrt{18-x}}{x-2} =\\ \dfrac{4-\sqrt{18-x}}{x-2} \dfrac{4+\sqrt{18-x}}{4+\sqrt{18-x}}= \\ \dfrac{16-(18-x)}{(x-2)(4+\sqrt{18-x})} =\\ \dfrac{1}{4+\sqrt{18-x}}$$

now plug x=2 in

Apr 17, 2019