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Find the limit of each using algebraic techniques.  

 

1.

 

2. 

 Apr 17, 2019
 #1
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1) should be obvious

 

2)

\(\dfrac{4-\sqrt{18-x}}{x-2} =\\ \dfrac{4-\sqrt{18-x}}{x-2} \dfrac{4+\sqrt{18-x}}{4+\sqrt{18-x}}= \\ \dfrac{16-(18-x)}{(x-2)(4+\sqrt{18-x})} =\\ \dfrac{1}{4+\sqrt{18-x}}\)

 

now plug x=2 in

 Apr 17, 2019

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