I'm really stuck on this:
Triangle $ABC$ is isosceles with $AB = AC$, and is inscribed in a circle. If $AP = 11$ and $PQ = 5$, then what is $AB^2$?
AQ is a diameter of a circle.
If AP * PQ = 55 then BP * PC = 55
AB = sqrt(AP2 + BP2) = 4√11
