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I'm really stuck on this:

 

Triangle $ABC$ is isosceles with $AB = AC$, and is inscribed in a circle.  If $AP = 11$ and $PQ = 5$, then what is $AB^2$?

 

 Dec 30, 2020
 #1
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AQ is a diameter of a circle.

 

If AP * PQ = 55 then BP * PC = 55      

 

AB = sqrt(AP2 + BP2) = 4√11

 Dec 30, 2020
edited by Guest  Dec 30, 2020

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