If a is a constant such that \(9x^2 + 24x + a\) is the square of a binomial, then what is a?
a is 16, since the binomial is of form (3x+4)^2 since 3^2=9 and 3*4*2=24. 4^2=16 im sorry that this isnt clear or if it's wrong.
+36915 9x^2 + 24x + a =
9 (x^2 + 24/9 x + a/9) 'complete the square'
9(x^2 + 24/9x + 144/81) where 144/81 = a/9 a = 16
9 ( x + 12/9)^2
9 x^2 + 24x + 16 =
(3x+4)^2
