The line x = k intersects the graph of the parabola x = -2y^2 - 3y + 5 at exactly one point. What is k?
+36916 the only way the line can intersect this sideways parabola is if it is at the apex - b/2a = 3/-4 = - .75
Sub this value of y into the equation to calculate 'k'
Another way
the discriminant must = 0 for only one intersection
k = -2y^2-3y+5
0 = -2y^2-3y+ ( 5-k)
b^2 - 4ac = 0
(-3)^2 - 4(-2)(5-k) = 0
9 +40 - 8k = 0
49 = 8k
k = 49/8 = 6 1/8 or 6.125
