+16 Find a polynomial \(f(x)\) of degree \(5\) such that both of these properties hold:
\(f(x)\) is divisible by \(x^3\).
\(f(x) + 2\) is divisible by \((x+1)^3\).
Since f(x) is divisible by x^3, f(x) is of the form ax^5 + bx^4 + cx^3.
You then want ax^5 + bx^4 + cx^3 + 2 to be divisible by (x + 1)^3. Using long division, you get the equations
-10a + 6b - 3c = 0
4a - 3b + 2c = 0
-a + b - c + 2 = 0
==> a = 6, b = 16, c = 12
So f(x) = 6x^5 + 16x^4 + 12x^3.
