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Heisenberg's Uncertainty Principle says that the product of the error in the measurement of a particle's momentum and the error in the measurement of a particle's position must be at least Planck's constant divided by 4π. Suppose the error in the measurement of the momentum of a particle is halved. By how many percent does the minimum error in the measurement of its position increase?

 

 

 

I NEED HELP!!!! PLZ HELP!!!!! MEANS A LOT TO ME

 Mar 19, 2020
 #1
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m * p  = h / (4pi)       if  m is 1/2

1/2 m  * 2p = h/(4pi)       p will double to keep the constant the same....  a 100% increase

 Mar 19, 2020
 #2
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Don't overthink this problemwink

 

What you should know about this rule is that the constant p will ALWAYS double no matter what m is. So, the percent increase is always 100%.

 Mar 19, 2020

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