Heisenberg's Uncertainty Principle says that the product of the error in the measurement of a particle's momentum and the error in the measurement of a particle's position must be at least Planck's constant divided by 4π. Suppose the error in the measurement of the momentum of a particle is halved. By how many percent does the minimum error in the measurement of its position increase?
I NEED HELP!!!! PLZ HELP!!!!! MEANS A LOT TO ME
+36916 m * p = h / (4pi) if m is 1/2
1/2 m * 2p = h/(4pi) p will double to keep the constant the same.... a 100% increase
