Find the ordered triple \((p,q,r)\) that satisfies the following system:
\(p-2q=0, q-2r=0, p+r=5.\)
Alright!
Substitution of p=2q!
q-2r=0, 2q+r=5
Substitude q=2r!
2*2r+r=5
Substitude r=1!
q=2*1
q=2
p=22
r=1
babababowwwwwww!
Yay!
