Write a quadratic relation in the form π¦ = ππ₯ 2 + ππ₯ + π with roots 4 and β 3 and passing through the point (3, -12).
Roots 4 and -3 means
y = a(x-4)(x+3)
y = a (x^2 -x -12) when x = 3 y = -12
-12 = a (3^2 -3-12)
-12 = a ( -6)
a = 2
y = 2x^2 - 2x- 24