the question is:
(cos(pi/6))(sin(pi/5))-(sin(pi/6))(cos(pi/5))
and the answers are either:
a) cos(11/30 pi)
b) sin (11/30 pi)
c) cos (pi/30)
d) sin (pi/30)
It's D sin(pi/30)
Using ...... sin (A - B) = sinAcosB - sinBcosA ......and we have.....
(cos(pi/6))(sin(pi/5))-(sin(pi/6))(cos(pi/5)) =
sin( pi/5 - pi/6) =
sin (pi / 30)