Solve the following systems of equations.
[1] 4x² + 8x + 5 - y = 1
3x² - x + 3 = y + x + 8
[1] 4x² + 8x + 5 - y = 1
3x² - x + 3 = y + x + 8
We can write
y = 4x^2 + 8x + 4 and
y = 3x^2 -2x - 5
Set these equal
4x^2 + 8x + 4 = 3x^2 - 2x - 5 rearrange as
x^2 + 10x + 9 = 0 factor
(x + 9) ( x + 1) = 0 set both factors equal to 0 and solve and we get that
x = -9 and y = 3(-9)^2 -2(-9) - 5 = 256
x = -1 and y =3(-1)^2 -2(-1) - 5 = 0
So...the solutions are (-9, 256) and (-1, 0)