Solve the following systems of equations.

[1] 4x² + 8x + 5 - y = 1

3x² - x + 3 = y + x + 8

Guest Apr 19, 2019

#1**+1 **

[1] 4x² + 8x + 5 - y = 1

3x² - x + 3 = y + x + 8

We can write

y = 4x^2 + 8x + 4 and

y = 3x^2 -2x - 5

Set these equal

4x^2 + 8x + 4 = 3x^2 - 2x - 5 rearrange as

x^2 + 10x + 9 = 0 factor

(x + 9) ( x + 1) = 0 set both factors equal to 0 and solve and we get that

x = -9 and y = 3(-9)^2 -2(-9) - 5 = 256

x = -1 and y =3(-1)^2 -2(-1) - 5 = 0

So...the solutions are (-9, 256) and (-1, 0)

CPhill Apr 19, 2019