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Y = 2x^2 - 4x - 6

a.) convert to vertex form

b.) find x- intercept. Solutions must be exact

c.) find all values such that y > 0

d.) find the range of dunction

e.) when is the function decreasing?

Guest Dec 3, 2018

#1**+1 **

1

2 (x^2-2x) -6 complete the square

Y= 2 (x-1)^2 - 8

2

x intercept(s) happen when y = 0 set the equation to y=0

0 = 2(x-1)^2 - 8

4 = (x-1)^2

+- 2 = x-1

x = 3, -1

3

From 2 above (-inf,-1) U (3, +inf)

Range = all values of x are allowed in the domain...the range extends from the vertex at -8 to + inf [-8, +inf)

This is an upright parabola....the funtion is decreasing from -inf to the vertex (1,-8) or for values of x ( -inf ,1]

ElectricPavlov Dec 3, 2018