Please help with this question.
Find the sum of alldistinct of BC.
Hello Guest!
\(c^2=a^2+b^2-2bc\ cos\ \gamma\\ 4^2=x^2+10^2-2\cdot 10\cdot x\cdot cos\frac{\pi}{6}\\ x^2-20\cdot cos\frac{\pi}{6}\cdot x+100-16\\ x=8.66\pm\sqrt{8.66^2-84}\\ x\in \{\} \)
\(BC\in\{\}\)
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B
4
C 30° 10 A
4^2 = 10^2 + BC^2 - 2 (10)(BC) ( sqrt 3)/2)
16 = 100 + BC^2 - (10sqrt 3)BC
BC^2 - (10sqrt 3)BC + 84 = 0
[ No real solutions for BC since the discriminant is negative ]
Thanks for answering Asinus and CPhill!!!
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