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avatar+224 

 

 

 Feb 14, 2019
edited by oscar.a1551  Feb 15, 2019
 #1
avatar+98153 
+3

We will have the following form

 

y = Asin (Bx + C ) + D

 

A = the amplitude =  2

 

The period =  1 / frequency  =  1 / (1/ [4pi] ) =  =   4pi

 

B =  [ 2pi] / period  =   [ 2pi ] / [ 4pi]  =   1/2

 

C = phase shift  =  there is none....so.....C = 0

 

D = the shift up/down

Because the midline of the normal sine function is y = 0.....then the midline y = 2 shifts this up 2 units....so...D = 2

 

So.....the function is    

 

y = 2sin [ (1/2)x ] + 2

 

Here is the graph :

 

https://www.desmos.com/calculator/bmcanvqjfx

 

 

cool cool cool

 Feb 14, 2019
 #2
avatar+98153 
+2

Second one  .....using the same form as the first one

 

A = the amplitude = 4

 

B =  2pi / period  =  2pi / 12  =   pi / 6

 

C =  no phase shift =  0

 

D =  shift up/down = 1

 

The function is

 

y = 4 sin [ (pi / 6) x ]  + 1

 

Here's the graph :

 

https://www.desmos.com/calculator/laevedr8oc

 

 

cool cool cool

 Feb 14, 2019

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