What is the probability of obtaining exactly three "6" in 5 rolls of a fair dice?

Guest Jan 12, 2020

#2**0 **

You will need 3 6's and 2 not-6's.

The probability of getting a 6 is 1/6; the probability of getting a not-6 is 5/6.

(1/6)(1/6)(1/6)(5/6)(5/6) = 25/7776.

You will need to multiply this answer by the number of ways that 3 6's can be chosen: _{5}C_{3} = 10.

Answer = 10 x 25 / 7776 = 0.0322 or 125/3888.

geno3141 Jan 13, 2020