In Triangle ABC, Sin A =3/5, while Cos B = 5/13. What is the Value of cos C?
+23 We know that the cosine of A+B [cos(A + B)] is equal to -1 times cosC.
Moreover -1 times cosC is equal to cosA.cosB−sinA.sinB
Therefore,
=−(65/15−65/4.12)
= -(15 - 48) / 65
= 33/65
Hope this helped, and have a great day!
+23 Oops! I meant to say - [15/65 - 4.12/65], not −(65/15 − 65/4.12)!
