In Triangle ABC, Sin A =3/5, while Cos B = 5/13. What is the Value of cos C?

Guest Jan 13, 2022

#1**0 **

We know that the cosine of A+B [cos(A + B)] is equal to -1 times cosC.

Moreover -1 times cosC is equal to cosA.cosB−sinA.sinB

Therefore,

=−(65/15−65/4.12)

= -(15 - 48) / 65

= **33/65**

Hope this helped, and have a great day!

DreamingFox1214 Jan 13, 2022