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In Triangle ABC, Sin A =3/5, while Cos B = 5/13. What is the Value of cos C?

 Jan 13, 2022
 #1
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We know that the cosine of A+B [cos(A + B)]  is equal to -1 times cosC.

 

Moreover -1 times cosC is equal to cosA.cosB−sinA.sinB

 

Therefore,

 

 

=−(65/15​−65/4.12​)

 

= -(15 - 48) / 65

= 33/65

 

Hope this helped, and have a great day!

 Jan 13, 2022
 #2
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Oops! I meant to say - [15/65 - 4.12/65], not −(65/15 ​− 65/4.12​)!

DreamingFox1214  Jan 13, 2022
 #3
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cos C = 16/65

 Jan 13, 2022

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