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(m^-6) *(n^-3) *(p^-9) / [(m^-20)*(n^-12)*(p^-24])

 Feb 10, 2017
 #1
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By the way it is like a fraction

 Feb 10, 2017
 #2
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Simplify the following:
1/((m^6 n^3 p^9)/(m^20 n^12 p^24))

Combine powers. (m^6 n^3 p^9)/(m^20 n^12 p^24) = m^(6 - 20) n^(3 - 12) p^(9 - 24):
1/(m^6 - 20 n^3 - 12 p^9 - 24)

6 - 20 = -14:
1/(m^-14 n^(3 - 12) p^(9 - 24))

3 - 12 = -9:
1/((n^-9 p^(9 - 24))/m^14)

9 - 24 = -15:
1/(p^-15/(m^14 n^9))

1/(1/(m^14 n^9 p^15)) = 1/(1/(m^14 n^9 p^15))×(m^14 n^9 p^15)/(m^14 n^9 p^15) = (m^14 n^9 p^15)/((m^14 n^9 p^15)/(m^14 n^9 p^15)) = m^14 n^9 p^15 = m^14 n^9 p^15:
Answer: |m^14 n^9 p^15

 Feb 10, 2017

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