A quadratic of the form \(-2x^2 + bx + c\) has roots of \(x = 3 + \sqrt{5}\) and \(x = 3 - \sqrt{5}.\) The graph of \(y = -2x^2 + bx + c\) is a parabola. Find the vertex of this parabola.

I don't know where to start with this, let alone solve it.

Can someone please explain to me?

Thanks in advance.

Guest Apr 15, 2020