+0  
 
0
47
1
avatar

A quadratic of the form \(-2x^2 + bx + c\) has roots of \(x = 3 + \sqrt{5}\) and \(x = 3 - \sqrt{5}.\) The graph of \(y = -2x^2 + bx + c\) is a parabola. Find the vertex of this parabola.

 

I don't know where to start with this, let alone solve it.

Can someone please explain to me?

Thanks in advance.

 Apr 15, 2020
 #1
avatar
0

The vertex is at (4,-16).

 May 12, 2020

18 Online Users

avatar