1) The area of the equilateral triangle with a side of 12cm = 6 * 12[sqrt(3)/2] = [72/2] * sqrt(3) = 36sqrt(3) cm^2
The area of the square with the diagonal of 8 cm = [8/sqrt(2)]^2 = [64/2] = 32 cm^2
2) Area of a square with a diagonal of 12sqrt(2)cm ........the side = 12sqrt(2)/sqrt(2) = 12cm
So the area = side^2 = [12cm]^2 = 144 cm^2
1) The area of the equilateral triangle with a side of 12cm = 6 * 12[sqrt(3)/2] = [72/2] * sqrt(3) = 36sqrt(3) cm^2
The area of the square with the diagonal of 8 cm = [8/sqrt(2)]^2 = [64/2] = 32 cm^2
2) Area of a square with a diagonal of 12sqrt(2)cm ........the side = 12sqrt(2)/sqrt(2) = 12cm
So the area = side^2 = [12cm]^2 = 144 cm^2