#1**+1 **

Any number, * except for zero,* raised to the power of zero equals 1 .

Here is one way of thinking about why this is. I've never heard it explained like this, but I really like his explanation! I will probably think of it this way from now on!

https://www.youtube.com/watch?v=dAvosUEUH6I

And....I was trying to find a good video explaining it another way, but I couldn't really find a good one. Here's a pretty good answer to your question that you can read through if you want.

hectictar
Jun 3, 2017

#2**+2 **

I think I have an explanation that is simple to understand! In advance, I have not referenced any of Hecticlar's sources before writing this explanation, so mine could be similar or different. To start, I am going to make a table of powers that we can calculate:

\(2^n\) | Written-out | Result |

\(2^5\) | 2*2*2*2*2 | 32 |

\(2^4\) | 2*2*2*2 | 16 |

\(2^3\) | 2*2*2 | 8 |

\(2^2\) | 2*2 | 4 |

\(2^1\) | 2 | 2 |

\(2^0\) | ? | ? |

\(2^{-1}\) | 1/(2) | 1/2 |

\(2^{-2}\) | 1/(2*2) | 1/4 |

\(2^{-3}\) | 1/(2*2*2) | 1/8 |

\(2^{-4}\) | 1/(2*2*2*2) | 1/16 |

\(2^{-5}\) | 1/(2*2*2*2*2) | 1/32 |

Do you notice a pattern? I do. As you go down the list, you can divide by 2 to get the next number in the sequence! FIrst, I'll generalize this statement:

\(\frac{2^n}{2}=2^{n-1}\)

What I have done here is manipulate the powers so that I can circumvent raising to the power of 0. If I make n=1, I will raise to the power of zero and get a result of what that answer should be. Let's try it!

\(\frac{2^1}{2}=2^{1-1}\) | Let's simplify the right hand side first by doing 1-1 |

\(\frac{2^1}{2}=2^0\) | Woah! Evaluate the left hand side to figure out what 2^0 truly equals. |

\(\frac{2}{2}=2^0\) | |

\(1=2^0\) | |

We can generalize this further to say that any number raised to the power of zero is 1 using some algebra:

\(1=\frac{x^n}{x^n}\hspace{1mm},x\neq0\) | This statement is true because any number divided by itself is one! I'll use an exponent rule that says that \(\frac{x^n}{x^n}=x^{n-n}\) |

\(1=x^{n-n}\) | n-n=0, so let's simplify that |

\(1=x^0\hspace{1mm},x\neq0\) | This is saying that any number to the power of zero is one. |

TheXSquaredFactor
Jun 3, 2017