+20 Two consecutive numbers in a geometric sequence are 12 and 15.
a) Determine the common ratio.
b) If t4 = 12, what is the value of t1 as an exact value?
c) Determine the value of t20, rounded to the nearest tenth.
+605 a) $\frac{15}{12}=\frac{5}{4}$
b) $12\left(\frac{4}{5}\right)^3=\frac{768}{125}$
c) $12*\left(\frac{5}{4}\right)^{16}\approx 426.32$
