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Two consecutive numbers in a geometric sequence are 12 and 15.

 

a) Determine the common ratio.

 

b) If t4 = 12, what is the value of t1 as an exact value?

 

c) Determine the value of t20, rounded to the nearest tenth.

 Feb 23, 2021
 #1
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a) $\frac{15}{12}=\frac{5}{4}$

b) $12\left(\frac{4}{5}\right)^3=\frac{768}{125}$

c) $12*\left(\frac{5}{4}\right)^{16}\approx 426.32$

 Feb 23, 2021

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